Question

quantos termos possui a pg (6,12..., 384)?

Answer 1

an=a1.q^(n-1)
384=6.2^(n-1)
384/6=2^(n-1)
64=2^(n-1)
2^6=2^(n-1)
n-1=6
n=6+1
n=7 termos

Answer 2

a1 = 6
a2 = 12
q = 12/6 = 2 ***
an = 384
384 = 6 * 2ⁿ⁻¹
2ⁿ⁻¹ = 384/6 =64 =2⁶
n - 1 = 6
n = 6 + 1 = 7 ****