• Matéria: Matemática
  • Autor: joycerenata91
  • Perguntado 8 anos atrás

dada a lei da funçao f(x)=5x-2 determine o valor de x de modo que
A)f(x)=0
B)f(x)=3
C)f(x)=-10
D)f(x)=13

Respostas

respondido por: Anônimo
371
f(x)=5x-2 determine o valor de x de modo queA)
f(x)=0
0 = 5x - 2
2 = 5x
5x = 2
x = 2/5

B)
f(x) = 3

f(x) = 5x - 2
3 = 5x - 2
3 + 2 = 5x
5 = 5x
5x = 5
x = 5/5
x = 1
*********************
C)
f(x) = - 10

f(x) = 5x - 2
- 10 = 5x - 2
- 10 + 2 = 5x
- 8 = 5x
5x = - 8
x = - 8/5

***********************
D)
f(x) = 13

f(x) = 5x - 2
13 = 5x - 2
13 + 2 = 5x
15 = 5x
5x = 15
x = 15/5
x = 3

******************************
respondido por: maikenio1234
62

F(x)=5x-2

A)

f(x)=0

0 = 5x - 2

2 = 5x

5x = 2

x = 2/5

B)

f(x) = 3

f(x) = 5x - 2

3 = 5x - 2

3 + 2 = 5x

5 = 5x

5x = 5

x = 5/5

x = 1

C)

f(x) = - 10

f(x) = 5x - 2

- 10 = 5x - 2

- 10 + 2 = 5x

- 8 = 5x

5x = - 8

x = - 8/5

D)

f(x) = 13

f(x) = 5x - 2

13 = 5x - 2

13 + 2 = 5x

15 = 5x

5x = 15

x = 15/5

x = 3

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