Question

A)Log (1/6)
2

B) log (3/2)
2/3

Answer 1

A)Log (1/6) = x   ==> 2^x = 1/6 ==> 2^x = 6^-1         2

Como as bases são diferentes . V = Ф
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B) log (3/2) = y ==> (2/3)^x = 3/2 ==> (2/3)^x = (2/3)^-1  ==> y = - 1
        2/3