Question

Dada a funçao f(x)=x²-3x-10 calcule
f(-2)
f(-3)
f(0)
f(5)

Answer 1

f(-2) = (-2)² -3(-2) -10 = 4 +6 -10 = 0

f(-3) = (-3)² -3(-3) -10 = 9 +9 -10 = 8

f(0) = 0 -3(0) -10 = -10

f(5) = 25 -15 -10 = 0

Answer 2

f(x)=x²-3x-10

f(-2) = ( - 2)² - 3 • ( - 2) - 10

f(-2) = 4 + 6 - 10

f(-2) = 10 - 10

f(-2) = 0

f(-3) = ( - 3)² - 3 • ( - 3) - 10

f(-3) = 9 + 9 - 10

f(-3) = 18 - 10

f(-3) = 8

f(0) = 0² - 3 • 0 - 10

f(0) = 0 - 0 - 10

f(0) = - 10

f(5)= 5² - 3 • 5 - 10

f(5) = 25 - 15 - 10

f(5) = 10 - 10

f(5) = 0