Question

como se resolve a equaçao 12x²-7x+1=0

Answer 1

12x² - 7x + 1 = 0 
x² - 7/24x = - 1/12 + (- 7/24)² 
x² - 7/24x = (- 48 + 49)/576 
(x - 7/24)² = 1/576 
x - 7/24 = ± 1/24 

= x + (- 7 + 1)/24, = x - 6/24, = x - 1/4, = 4x - 1 
= x + (- 7 - 1)/24, = x - 8/24, = x - 1/3, = 3x - 1 

resposta: (4x - 1)(3x - 1) são os fatores.

Answer 2

Basta usar a formula de bhaskara

Δ = b² - 4ac
Δ = -7² - 4.1.12
Δ = 49 - 48
Δ = 1

x = -b +/- √Δ/2a
x = -(-7) +/- √1 / 2.12
x = 7 +/- 1/ 24

x1 = 7+1/24 = 8/24 = 1/3

x2 = 7-1/24 = 6/24 = 1/4

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