Question

Calcule f(x)=3x²+2x+6 sendo f(-1) f(3) f(0) f(-4)

Answer 1

 f(x)=3x²+2x+6 sendo f(-1) f(3) f(0) f(-4)
 f(-1) =  3(-1)²+2(-1)+6==> 3.(1)-2+6 ==> 3-2+6 ==> 7
 f(3) =   3(3)²+2(3)+6==> 3.(9)+6+6 ==> 27+6+6 ==> 39
 f(0) =   3(0)²+2(0)+6==>  0-0+6 ==> 0+6 ==> 6
 f(-4) =  3(-4)²+2(-4)+6==> 3.(16)-8+6 ==> 48-8+6 ==> 40