Question

Dada a função y = 2 x ³ + 3 x ² – 4 x + 1, o valor de y’(1) é:

Answer 1

y = 2 x ³ + 3 x ² – 4 x + 1

y' = 6x² + 6x - 4

y’(1)  = 6(1)² + 6(1) - 4 ==> 6.1 + 6 - 4 ==> 6 + 6 - 4 ==> 8