Question

como fazer o arranjo da equaçao e depois calcule suas raizes : 
(3x+1) + (x-2) (x+1) = -1

4000/x + 50 = 4000/x-4

Answer 1

(3x+1) + (x-2) (x+1) = -1

3x + 1 +  x² - x - 2 = - 1
 x²  + 3x + 1 - x - 2 + 1 = 0
 x²  + 2x  = 0

x(x +2 ) = 0

x1 = 0 

x2 + 2 = 0 

x2 = - 2


4000/x + 50 = 4000/x-4

4000  + 50 = 4000                       mmc = x(x-4)
  x                x-4
4000(x-4) +  50x(x-4) = 4000x
4000x - 16000 +  50x² - 200  = 4000x
4000x - 16000 +  50x² - 200 - 4000x = 0

- 16000 +  50x² - 200  = 0
     50x²  = 16200
       x²  = 16200
                  50
     x²  = 324
      x = +/- 18

Answer 2

$\huge{\boxed{\boxed{ \tt \: \left(3x+1\right)+\left(x-2\right)\left(x+1\right)=-1\: }}}\\\\\huge{\boxed{\boxed{ \tt \:x^2+2x-1=-1 \: }}}\\\\\huge{\boxed{\boxed{ \tt \: x^2+2x-1+1=-1+1\: }}}\\\\\huge{\boxed{\boxed{ \tt \:x^2+2x=0 \: }}}\\\\\huge{\boxed{\boxed{ \tt \: x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}\: }}}\\\\\huge{\boxed{\boxed{ \tt \:x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1} \: }}}$

$\huge{\boxed{\boxed{ \tt \:x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\ \: }}}$

$\huge{\boxed{\boxed{ \tt \: x=0,\:x=-2<<<\: }}}$

$\huge{\boxed{\boxed{ \tt \:=====\: }}}$

$\huge{\boxed{\boxed{ \tt \:\frac{4000}{x+50}=\frac{4000}{x-4} \: }}}\\\\\huge{\boxed{\boxed{ \tt \:4000\left(x-4\right)=\left(x+50\right)\cdot \:4000 \: }}}\\\\\huge{\boxed{\boxed{ \tt \:x=\frac{+}{-18} \: }}}$