Question

Escreva os 6 primeiros termos das sequencias a seguir com n e N*?  a) (2n-6)= 
b) (3n+3)= 
c) (4n-3)= 
d) (5n-9)= 

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Answer 1

a) (2n-6)= ( - 4, - 2, 0, 2, 4, 6)

n1= 2.1-6= 2-6= = - 4
n2= 2.2-6= 4-6= = - 2
n3= 2.3-6= 6-6= = 0
n4= 2.4-6= 8-6= = 2
n5= 2.5-6=10-6= = 4
n6= 2.6-6= 12-6= = 6

b) (3n+3)= (  6, 9, 12, 15, 18, 21 )

n1= 3.1+3= 3+3= 6
n2= 3.2+3= 6+3= 9
n3= 3.3+3= 9+3= 12
n4= 3.4+3= 12+3= 15
n5= 3.5+3=15+3=18
n6= 3.6+3=18+3= 21

c) (4n-3)= ( 1, 5, 9, 13, 17, 21)

n1= 4.1-3= 4-3=  1
n2= 4.2-3= 8-3=  5
n3= 4.3-3= 12-3= 9
n4= 4.4-3= 16-3= 13
n5= 4.5-3=20-3=  17
n6= 4.6-3=24-3=  21

d) (5n-9)= ( - 4, 1, 6, 11, 16, 21)

n1=5.1-9= 5-9= = - 4
n2= 5.2-9= 10-9= 1
n3= 5.3-9= 15-9= 6
n4=5.4-9= 20-9= 11
n5= 5.5-9=25-9=16
n6= 5.6-9= 30-9= 21