• Matéria: Matemática
  • Autor: joorgefspJorge
  • Perguntado 9 anos atrás

Preciso de ajuda urgente, (0.25) elevado a 2x = raiz quadrada de 32

Respostas

respondido por: korvo
0
(0,25)^{2x}= \sqrt{32}\\\\
\left( \dfrac{25}{100}\right)^{2x}= \sqrt{2^5}\\\\
\left( \dfrac{25\div25}{100\div25}\right)^{2x}= 2^{ \tfrac{5}{2}}\\\\
\left( \dfrac{1}{4}\right)^{2x}=2^{ \tfrac{5}{2}

\left( \dfrac{1}{2^2}\right)^{2x}=2^{ \tfrac{5}{2}}\\\\
(2^{-2})^{2x}}=2^{ \tfrac{5}{2} }\\\\
\not2^{-4x}=\not2^{ \tfrac{5}{2}}\\\\
-4x= \dfrac{5}{2}\\\\
\huge\boxed{x=- \dfrac{5}{8}}}
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