Question

Preciso saber: log com base √8 elevado a 4 = x

Answer 1

$\sqrt{8} ^{x} = 4 =\ \textgreater \ 8^{ \frac{x}{2} }=2^{ \frac{3x}{2} } = 2^{2}\\\\ \frac{3x}{2} = 2\\\\ 3x = 4\\\\ x = \frac{4}{3}$