Question

Se f(x)=x²+x, g(x)=2x-1 e h(x)=3x. Calcule: h[f(g(x))]=

Answer 1

Bonsouir cher ami !!

Vamos lá !!

h[f(g(x))]= 3*[ (2x - 1) + ( 2x - 1)]
h[f(g(x))]=3*( 4x - 2)
h[f(g(x))]= 12x - 6 

Então : 

=>  12x - 6 = 0
=> 12x = 6
=> x = 1/2 

Fazendo a prova real temos :

g(x) = 2x - 1
=> 2x - 1 = 0
=>2*1/2 - 1= 0
=> 1 - 1 = 0

OK..

A Bientot!!