Question

30+40-20-50+50+40×30×50÷50

Answer 1

30+40-20-50+50+40×30×50÷50

Primeiro resolvemos as divisões e multiplicações e, depois, as adições e subtrações: 

30+40-20-50+50+40×30×50÷50 = 
30+40-20-50+50+(40×30)×(50÷50) = 
30+40-20-50+50+(1200)×(1) = 
30+40-20-50+50+(1200) = 
(30+40)-20+(-50+50)+(1200) = 
(70-20)+(0)+1200 = 
50 + 1200 = 
1250

Answer 2

30+40-20-50+50+40×30×50÷50 
70-20-50+50+40x30x50÷50
50-50+40x30x50÷50
0+40x30x50÷50
40x30x50÷50
1.200x50÷50
60000÷50
1.200