Question

sendo f(x)= 2x³-15x²+36x-7 e g(x)=x³-6x²+11x-6, determine: f'(0)-3g'(1)

Answer 1

$f(x)=2x^{ 3 }-15x^{ 2 }+36x-7\\ g(x)=x^{ 3 }-6x^{ 2 }+11x-6\\ \\ f(0)=2(0)^{ 3 }-15(0)^{ 2 }+36(0)-7\\ f(0)=-7\\ \\ g(1)=1^{ 3 }-6(1)^{ 2 }+11(1)-6\\ g(1)=1-6+11-6\\ g(1)=0\\ \\ f(0)-3g(1)=-7-3*0\\ f(0)-3g(1)=-7$