Question

{2X[7-(raiz quadrada de 16+1):5]:4}elevado à dois

Answer 1

$\left(\frac{2\left[7-\frac{\left(\sqrt{16}+1\:\right)}{5}\right]}{4}\right)^2\\ = \left(\frac{2\left[7-\frac{\left(4+1\:\right)}{5}\right]}{4}\right)^2 = \left(\frac{2\left[7-\frac{\left(5\:\right)}{5}\right]}{4}\right)^2 =\\\\\left(\:\frac{2\left[7-1\right]}{4}\right)^2 = \left(\frac{2\cdot 6}{4}\right)^2 = ( \frac{12}{4} )^2= 3^2 = 9$