Question

x²+3   -3 =x
  2
RESOLVA A EQUACÃO DE 2 GRAU POR BHASKARA

Answer 1

x²+3 - 3 = x
 2

x² + 3 = 2x+6
x²-2x -3=0
Δ=(-2)²-4(1)(-3)
Δ=4+12=16
Δ=16
x=-(-2)+-√16
         2(1)
x= 2+-4
       2
x¹=6/2 = 3
x²=-2/2=-1

Answer 2

x²+3 - 3 = x
 2

x² + 3 = 2x+6
x²-2x - 3 = 0

Δ= 16

x1 = 3    :   x2 = - 1