Question

qual o número complexo z ,tal que i.z+(z+z)=1+2i

Answer 1

iz+2z = 1+2i
z(i+2) = 1+2i
z = (1+2i)/(i+2)
z = (1+2i)*(i-2) / (i+2)*(i-2)
z = (i-2+2i²-4i) / i²-2²
z = (-3i-2-2) / -1-4
z = (-3i-4)/-5