Respostas
respondido por:
1
Boa tarde!
Solução!
![A^{2}=(3x)^{2} +(4x)^{2}\\\\\\
A^{2}=9 x^{2} +16x^{2}\\\\\\
A^{2}=25 x^{2} \\\\\\
A= \sqrt{25 x^{2} }\\\\\
A= \sqrt{5^{2} x^{2} }\\\\\\
\boxed{A= 5x}](https://tex.z-dn.net/?f=A%5E%7B2%7D%3D%283x%29%5E%7B2%7D+%2B%284x%29%5E%7B2%7D%5C%5C%5C%5C%5C%5C%0AA%5E%7B2%7D%3D9+x%5E%7B2%7D++%2B16x%5E%7B2%7D%5C%5C%5C%5C%5C%5C%0A+A%5E%7B2%7D%3D25+x%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%0AA%3D+%5Csqrt%7B25+x%5E%7B2%7D+%7D%5C%5C%5C%5C%5C%0AA%3D+%5Csqrt%7B5%5E%7B2%7D++x%5E%7B2%7D+%7D%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BA%3D+5x%7D+%0A%0A+++ "A^{2}=(3x)^{2} +(4x)^{2}\\\\\\
A^{2}=9 x^{2} +16x^{2}\\\\\\
A^{2}=25 x^{2} \\\\\\
A= \sqrt{25 x^{2} }\\\\\
A= \sqrt{5^{2} x^{2} }\\\\\\
\boxed{A= 5x}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
kinsley:
obrigada :)
respondido por:
1
A²= (3x)² + (4x)²
A²=9x² + 16x²
A=√9x² + 16x²
A=√25x²
A=5x
A²=9x² + 16x²
A=√9x² + 16x²
A=√25x²
A=5x
Perguntas similares
7 anos atrás
7 anos atrás
7 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás
9 anos atrás