Question

resolva as equasçoes de 2o grau unsando a forma de bhaskara: a) x2+8x+12=0?

Answer 1

Oi Priscila

x² + 8x + 12 = 0

a = 1, b = 8, c = 12

delta
d² = b² - 4ac
d² = 8² - 4"1*12
d² = 64 - 48 = 16

d = 4

x1 = (-8 + 4)/2 = -4/2 = -2
x2 = (-8 - 4)/2 = -12/2 = -6 

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Answer 2

x2+8x+12=0
delta= b ao quadrado - 4.a.c
delta=(8)2-4.1.12
delta=64-48
delta=16
x= -b +ou - raiz de delta sobre 2.a
x'= -8+4/2.1
x'= -4/2
x'= -2
x''= -8-4/2.1
x''= -12/2
x''= -6