Question

(2x/4-2)=(3x/8+3) me ajudeeeeeemmmmmmmmmmmmmm

Answer 1

$\frac{2x}{4}-\frac{2}{1}=\frac{3x}{8}+\frac{3}{1}\\\\ Primeiro\ \ tira\ \ o\ \ MMC \\\\ \left\{\begin{array}{ccc}4,1,8,1|2 \\\\ 2,1,4,1|2\\\\1,1,2,1|2\\\\1,1,1,1| \ \\ \\\boxed{\boxed{MMC \to 2*2*2 = 8}}\end{array}\right \\\\ \frac{2x}{4}-\frac{2}{1}=\frac{3x}{8}+\frac{3}{1} \\\\\frac{(2*2x)-(8*2)=(1*3x)+(8*3)}{8} \\\\ 4x-16=3x+24 \\\\Passa\ \ os\ \ valores\ \ para\ \ o\ \ outro\ \ lado \ \ do \ \ igual \ \ com \ \ o \ \\ sinal \ \ invertido \\\\ 4x-16=3x+24 \\\\ 4x-3x=16+24 \\\\ x = 40$

$Resposta \to \boxed{\boxed{x = 40}}$

Espero ter ajudado!