Question

s= - 27 - 6 t + t2 resultado

Answer 1

t²-6t-27=0

∆= (-6)²-4*1*(-27)
∆= 36+108
∆=144

t= -b±√∆/2a
t= -(-6)±√144/2*1
t=6±12/2

t1=6+12/2
t1=9

t2=6-12/2
t2= -3

RESPOSTA: t=9