Question

aplique na formula de delta(∆=b²-4•a•c); 5x²+4x-1=0

Answer 1

a= 5
b= 4
c= -1

∆=b²-4•a•c
∆ = (4)² - 4.5.(-1)
∆ = 16+20
∆ = 36

-b +- raiz de delta/ 2.a
-4 + 6/10
+2/10

-b +- raiz de delta/ 2.a
-4 -6/ 10
-10/10 -> -1