Question

Fatore completamente.
a) 10 a ² - 20a +10=
b) -2x² +8x -8=
c) x³ - 10 + 25 x =

Answer 1

a) 10 a ² - 20a +10= 10( a ² - 2a + 1) = 10(a-1)^2

b) -2x² +8x -8= -2( x² - 4x + 4) = -2(x - 2)^2

c) x³ - 10x²  + 25 x = x( x² - 10x + 25) ==>  x(x - 5)^2 

Answer 2

10a²-20a-10 (:10) = 1a²-2a-1
delta= (-2)²-4.1.1= 4-4=0
a= -(-2) ± √0/ 2.1
a= 2±0/2 • 2+0/2= 2/2=1
• 2-0/2= 2/2=1
S{1}