Question

considere as funções f(x)=ax+b com f(2)=16 e f(-3)=-9,então podemos afirmar que f (4/3)é igual a:

Answer 1

16 = 2a+b (I)

-9 = -3a+b (II)

(II) *-1 = 9 = 3a-b

(I)+(II) = 25 = 5a
a = 25/5
a = 5

16 = 2.5+b
16 = 10 + b
b = 6

f(4/3) = 5.4/3 + 6
f(4/3) = 20/3 + 6
f(4/3) = 20/3 + 18/3
f(4/3) = 38/3
f(4/3) ≈ 12,66