Paula aplicou R$ 12.650 em um fundo de investimento à taxa de juro simples de 3% ao ano.
a) Qual será o juro obtido após 3 anos?
b) Depois de quanto tempo Paula terá um montante de R $ 16.450,00?
Com contas por favor
Respostas
respondido por:
3
Bom dia Angêlo!
Solução!
![J= \dfrac{C.i.t}{100}\\\\\\\
J= \dfrac{12650\times3.3}{100}\\\\\\\\
J=12650\times0,03.3\\\\\\\\
\boxed{J=11.385,0}](https://tex.z-dn.net/?f=J%3D+%5Cdfrac%7BC.i.t%7D%7B100%7D%5C%5C%5C%5C%5C%5C%5C%0AJ%3D+%5Cdfrac%7B12650%5Ctimes3.3%7D%7B100%7D%5C%5C%5C%5C%5C%5C%5C%5C%0AJ%3D12650%5Ctimes0%2C03.3%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BJ%3D11.385%2C0%7D++++ "J= \dfrac{C.i.t}{100}\\\\\\\
J= \dfrac{12650\times3.3}{100}\\\\\\\\
J=12650\times0,03.3\\\\\\\\
\boxed{J=11.385,0}")
Fazendo a formula do montante!
![M=C(1+i)^{t}\\\\\\
16450=12650(1+0,03)^{t}\\\\\\
16450=12650(1,03)^{t}\\\\\\
\dfrac{16450}{12650}=(1,03)^{t}\\\\\\\
1,3=(1,03)^{t}\\\\\\\
t(1,03)=1,3\\\\\
t= \dfrac{1,3}{1,03}\\\\\\\
t= \dfrac{log(1,3)}{log(1,03)}\\\\\\\
t= \dfrac{0,11394}{0,01283} \\\\\\
t=8,880\\\\\
\boxed{t=8~anos}](https://tex.z-dn.net/?f=M%3DC%281%2Bi%29%5E%7Bt%7D%5C%5C%5C%5C%5C%5C%0A16450%3D12650%281%2B0%2C03%29%5E%7Bt%7D%5C%5C%5C%5C%5C%5C%0A16450%3D12650%281%2C03%29%5E%7Bt%7D%5C%5C%5C%5C%5C%5C%0A+%5Cdfrac%7B16450%7D%7B12650%7D%3D%281%2C03%29%5E%7Bt%7D%5C%5C%5C%5C%5C%5C%5C%0A1%2C3%3D%281%2C03%29%5E%7Bt%7D%5C%5C%5C%5C%5C%5C%5C%0At%281%2C03%29%3D1%2C3%5C%5C%5C%5C%5C%0At%3D+%5Cdfrac%7B1%2C3%7D%7B1%2C03%7D%5C%5C%5C%5C%5C%5C%5C%0At%3D++%5Cdfrac%7Blog%281%2C3%29%7D%7Blog%281%2C03%29%7D%5C%5C%5C%5C%5C%5C%5C%0At%3D+%5Cdfrac%7B0%2C11394%7D%7B0%2C01283%7D+%5C%5C%5C%5C%5C%5C%0At%3D8%2C880%5C%5C%5C%5C%5C%0A%5Cboxed%7Bt%3D8%7Eanos%7D++++++ "M=C(1+i)^{t}\\\\\\
16450=12650(1+0,03)^{t}\\\\\\
16450=12650(1,03)^{t}\\\\\\
\dfrac{16450}{12650}=(1,03)^{t}\\\\\\\
1,3=(1,03)^{t}\\\\\\\
t(1,03)=1,3\\\\\
t= \dfrac{1,3}{1,03}\\\\\\\
t= \dfrac{log(1,3)}{log(1,03)}\\\\\\\
t= \dfrac{0,11394}{0,01283} \\\\\\
t=8,880\\\\\
\boxed{t=8~anos}")
Boa tarde!
Bons estudos!
Solução!
Fazendo a formula do montante!
Boa tarde!
Bons estudos!
respondido por:
4
Capital - R$ 12 650
juro simples - 3% = 3/100 = 0,03
tempo - 3 anos
Montante - 16450
A)
J = Cit
J = 12650.0,03.3
J = R$ 1138,50
B)
M = C + J
M = C + Cit
M = C(1 + 0,03t)
16450 = 12650(1 + 0,03t)
12650(1 + 0,03t) = 16450
1 + 0,03t = 16450/12650 16450/12650 = 1,300395257 = 1,3
1 + 0,03t = 1,3
0,03t = 1,3 - 1
0,03t = 0,3
t = 0,3/0,03
t = 10 anos
juro simples - 3% = 3/100 = 0,03
tempo - 3 anos
Montante - 16450
A)
J = Cit
J = 12650.0,03.3
J = R$ 1138,50
B)
M = C + J
M = C + Cit
M = C(1 + 0,03t)
16450 = 12650(1 + 0,03t)
12650(1 + 0,03t) = 16450
1 + 0,03t = 16450/12650 16450/12650 = 1,300395257 = 1,3
1 + 0,03t = 1,3
0,03t = 1,3 - 1
0,03t = 0,3
t = 0,3/0,03
t = 10 anos
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