Question

por favor me ajudem
tg²x=3√3·tgx

Answer 1

$tg^2x=3 \sqrt{3}tgx\\ \\ \frac{tg^x}{tgx}=3 \sqrt{3}\\ \\ tgx=3 \sqrt{3 }\\ \\ x=arctg(3 \sqrt{3} ) \approx 79^o$