Question

resolva esse sistema
x=y+1
2x²-3y²=6

Answer 1

■ x = y+1
■ 2x² - 3y² = 6

2(y+1)² - 3y² = 6 

2(y² + 2y + 1) - 3y²  = 6 

2y² + 4y + 2 - 3y² - 6  = 0 

-y² + 4y - 4 = 0  * (-1)

y² -4y + 4 = 0 ⇔ (y - 2)² = 0 ⇔ (y - 2) = 0 ⇔ y = 2 

■ x = y+1 ⇔ x = 2 + 1 ⇔ x = 3 

S = {3,2}

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13/10/2016
Sepauto 
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Answer 2

Precisa reorganizar

x-y=1
2x²-3y²=6

-3x²+3y²=3
2x²-3y²=6

-x²=9
-x=V9
-x = 3
x=-3

x=y+1
-3=y+1
y+1=-3
y=-3-1
y=-4