Question

A=[aij]3x2 tal que aij= 5i-3j.

Answer 1

[a11,a12]
[a21,a22]
[a31,a32] 3x2

a11= 5*1-3*1=2
a12= 5*1-3*2=-1
a21= 5*2-3*1=7
a22= 5*2-3*2=3
a31= 5*3-3*1=12
a32= 5*3-3*2=9

[ 2,-1]
[ 7, 3]
[12,9]3x2