Question

Derivada $f(x)= e^{2x} .cos x$

Answer 1

f(x)= e^x . cos(x) 

f'(x) = (e^x)' . cos(x) + (e^x). cos'(x)

f(x) = e^x . cos(x) + e^x . (-sen(x))

f(x) = e^x . cos(x) - e^x .sen(x)

f(x) = e^x[cos(x) - sen(x)]

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16/10/2016
Sepauto
SSRC
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