Question

Para quais valores reais de x tem-se x2-10x+25=0

Answer 1

x² - 10x + 25 = 0
Δ = 100 - 100
Δ = 0
x = (10 +- 0) /2
x = 5

Answer 2

Resposta:

$S=\{5\}$

Explicação passo-a-passo:

$x^{2} -10x+25=0\\\\a=1\\b=(-10)\\c=25$

$\Delta=b^{2} -4ac\\\Delta=(-10)^{2}-4\times1\times25\\\Delta=100-100\\\Delta=0$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-10)\pm\sqrt{0} }{2\times1} \\\\x=\frac{10\pm0}{2}$

$x_{1} =\frac{10+0}{2} =\frac{10}{2} =5\\\\x_{2}=\frac{10-0}{2}=\frac{10}{2} =5$