Question

(c-1)^2-(2c+4)(2c-4)???? Alguèm saberia resolver???

Answer 1

(c-1)^2-(2c+4)(2c-4) = c^2-2c+1-(4c^2-16) = c^2-2c+1-4c^2+16 = 
-3c^2-2c+17

Answer 2

$\large\begin{array}{l} \mathtt{(c-1)^2-(2c+4)(2c-4)}\\\\ =\mathtt{(c-1)(c-1)-(2c+4)(2c-4)}\\\\\\ \texttt{Aplique a propriedade distributiva nas multiplica\c{c}\~oes:}\\\\ =\mathtt{(c-1)\cdot c-(c-1)\cdot 1-[(2c+4)\cdot 2c-(2c+4)\cdot 4]}\\\\ =\mathtt{c^2-c-c+1-[4c^2+\,\diagup\!\!\!\!\!\! 8c-\diagup\!\!\!\!\!\! 8c-16]}\\\\ =\mathtt{c^2-2c+1-[4c^2-16]} \end{array}$

$\large\begin{array}{l} =\mathtt{c^2-2c+1-4c^2+16}\\\\ =\mathtt{c^2-4c^2-2c+1+16}\\\\ =\boxed{\begin{array}{c} \mathtt{-3c^2-2c+17} \end{array}}\quad\quad\checkmark \end{array}$


$\large\begin{array}{l} \texttt{D\'uvidas? Comente.}\\\\ \texttt{Bons estudos!} \end{array}$