Question

lim x3-1/x2-1 ,x tende a 1.

Answer 1

$\lim_{x \to \11} \frac{x^3-1}{x^2-1} = \lim_{x \to \11} \frac{(x-1)(x^2+x+1)}{(x-1)(x+1)} = \lim_{x \to \11} \frac{x^2+x+1}{x+1} = \frac{1^1+1+1}{1+1} = \frac{3}{2}$