Question

O valor da expressão:
x=[(1/2)^2 * (1/3)^3)]^4 * 1/2 * (1/3)^-3
escrita na potência de base 1/6 vale:

a) (1/6)^9

b) (1/6)^12

c) (1/6)^17

d) (1/6)7

Answer 1

   x= [(1/2)² * (1/3)³ )]⁴ * 1/2 * (1/3)⁻³ 
   x= (1/2)⁸ * (1/3)¹² * 1/2 * (1/3)⁻³ 
   x= [(1/2)⁸ * 1/2] * [(1/3)¹² * (1/3)⁻³]
   x= (1/2)⁹ * (1/3)⁹ 
   x= (1/6)⁹  <--- opção a)