Question

Os cinco primeiros termos da sequencia cujo termo geral é: $a_n: \sqrt[n+2]{n}$

Answer 1

$a_{1} = \sqrt[1+2]{1} = \sqrt[3]{1} = 1$

$a_{2} = \sqrt[2+2]{2} = \sqrt[4]{2}$

$a_{3} = \sqrt[3+2]{3} = \sqrt[5]{3}$

$a_{4} = \sqrt[4+2]{4} = \sqrt[6]{4} = \sqrt[3.2]{ 2^{2} } = \sqrt[3]{2}$

$a_{5} = \sqrt[5+2]{5} = \sqrt[7]{5}$