Question

os zeros da função y=x2+2x-3

Answer 1

x² + 2x + 3 = 0 

x² - 2x - 3 = 0 

[2 ± √(4 + 12)]/2 = 

(2 + √16)/2 = (2 + 4)/2 = 3 

(2 - √16)/2 = (2 - 4)/2 = -1

Answer 2

$y= x^{2} +2x-3$

a=1 b=2 c= -3

$delta = b^{2} -4.a.c$

$delta= 2^{2} -4.1.(-3)$

$delta= 4+12= 16$

$jogamos em baskara$

$x= \frac{ -b\frac{+}{-} \sqrt{delta} }{2.a}$

$x^{i} = \frac{-2 +4}{2} = \frac{2}{2}$
$x^{i} =1$

$x^{ii} = \frac{-2-4}{2} = \frac{-6}{2}$
 $x^{ii} =-3$