Question

Sendo p (x)=x^2-5x+6 obtenha os valores numéricos

P (1)
P (3)
P (2)
P (5)

Answer 1

p(x) = x² - 5x + 6

P(1) = 1² - 5.1 + 6
P(1) = 1 - 5 + 6
P(1) = 2

P(3) = 3² - 5.3 + 6
P(3) = 9 - 15 + 6
P(3) = 0

P(2) = 2² - 5.2 + 6
P(2) = 4 - 10 + 6
P(2) = 0

P(5) = 5² - 5.5 + 6
P(5) = 25 - 25 + 6
P(5) = 6