Question

x2-6x+9 formula de bhaskara

Answer 1

Vamos lá :

x² - 6x + 9 = 0

a = 1 ; b = - 6 ; c = 9

Δ = b² - 4ac
Δ = (-6)² - 4.1.9
Δ = 36 - 36
Δ = 0            √Δ  = 0

Aplica formula de Bhaskara ...

x = - b +/- √Δ / 2a
x = - (- 6) +/- 0 / 2.1
x = 6 +/- 0 / 2

x' = 6 + 0/2 = 6/2 = 3
x'' = 6 - 0/2 = 6/2 = 3

S = {3}

Espero ter ajudado !!!