Question

2 (2x-2)+5. (2-x)+6. (x+1)=0
por favor me ajudem

Answer 1

Nesses casos, aplicamos a distributiva.
 
2 ( 2x - 2 ) + 5 . ( 2 - x ) + 6 ( x + 1) = 0
4x - 4 + 10 - 5x + 6x + 6 = 0
4x - 5x + 6x - 4 + 10 + 6 = 0
5x + 12 = 0
5x = -12
x = -12/5

Answer 2

2(2x-2)+5.(2-x)+6.(x+1)=0
4x-4+10-5x+6x+6=0
4x+5x+6x=-4+10+6
15x=12
x=12:15
x=0,8