• Matéria: Matemática
  • Autor: Anzolin11
  • Perguntado 9 anos atrás

a) (1/3x+1/4)²
b) (3/6x²y+5)²
c) (3/7x4y-7x)²
d) (-x +4/3x²y)²
e) (3/5x+8/3y) (3/5x-8/3y)
f) (4/7x²y-9y²) (4/7x²y+9y²)
g) (4/7x4y5+3xy) (4/7x4y5-3xy)

Respostas

respondido por: 3478elc
1

  
 

a) (1/3x+1/4)² = 1/9x² + 1/6x + 1/16

b) (3/6x²y+5)²=   9/36x^4y² + 5x²y + 25

c) (3/7x4y-7x)² =  9/49x^8y² - 6x^5y + 49x²

d) (-x +4/3x²y)² = x² - 8/3x³y + 16/9x^4y²

e) (3/5x+8/3y) (3/5x-8/3y) = 9/25x² - 64/9y²

f) (4/7x²y-9y²) (4/7x²y+9y²) = 16/49 x^4y² - 81y^4

g) (4/7x4y5+3xy) (4/7x4y5-3xy) = 16/49x^8y^10 - 9x²y²
 




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