Question

me ajuda por favor, é pra amanhã e ainda n entendi, é uma equação exponencial.
√4x-2×-¹=4
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2 3 3

Answer 1

Olá Ryan,


$\frac{\sqrt{4^x}}{2}-\frac{2^{x-1}}{3}=\frac{4}{3}\\\\\frac{4^\frac{x}{2}}{2}-\frac{2^x.2^{-1}}{3}=\frac{4}{3}\\\\\frac{(2^2)^\frac{x}{2}}{2}-\frac{2^x.\frac{1}{2}}{3}=\frac{4}{3}\\\\\frac{2^x}{2}-\frac{2^x}{2}.\frac{1}{3}=\frac{4}{3}\\\\\frac{2^x}{2}-\frac{2^x}{6}=\frac{4}{3}\\\\2^x=y\\\\\frac{y}{2}-\frac{y}{6}=\frac{4}{3}\\\\\frac{3y}{6}-\frac{y}{6}=\frac{8}{6}\\\\3y-y=8\\2y=8\\\\y=\frac{8}{2}\\\\y=4\\\\2^x=4\\2^x=2^2\\\\\boxed{x=2}$

Dúvidas? comente