Question

biquadrada 4x⁴-5x²+1=0
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Answer 1

Vamos Lá:

4x^4 -5x^2 +1 =0

x^2 = y

4y^2 -5y +1 = 0

a = 4
b = -5
c = 1

Delta = b^2-4ac
Delta = -5^2 -4*4*1
Delta = 25 -16

Delta = 9


y = (-b+-raiz de delta)/2a

y = (5 +-Raiz de 9)/2*4
y = (5+-3)8

y' = (5+3)/8
y' = 8/8

y' = 1


y" = (5-3)/8
y" = 2/8 :2

y" = 1/4


x^2 = y
x^2 = y'
x^2 = 1
x = raiz de 1

x = +-1


x^2 = y"
x^2 = 1/4
x" = Raiz de 1/4

x" = +-1/2


S = {(+-1/2;+-1)}

Bons Estudos!!!