Question

como achar a raiz real desta equação: 9x²-3x/2=0

Answer 1

$9 x^{2} - \frac{3x}{2}=0 \\ \\ mmc=2 \\ \\ 18 x^{2} -3x=0 \\ \\ \Delta=(- 3)^{2} -4*18*0 \\ \\ \Delta=9-0 \\ \\ \Delta=9 \\ \\ \\ x= \frac{-(-3)+- \sqrt{9} }{2*18} \\ \\ x= \frac{3+-3}{36} \\ \\ \\ x'= \frac{3+3}{36} \\ \\ x'= \frac{6}{36} \\ \\ x'= \frac{1}{6} \\ \\ \\ x''= \frac{3-3}{36} \\ \\ x''= \frac{0}{36} \\  \\ x''=0 \\ \\ \\ \\ S=(0, \frac{1}{6})$