Question

quantos mol de Na2CO3existem em 132g de mol de Na2CO3?

Answer 1

1 mol de Na2CO3 vale tem 106g
então 106 --- 1 mol
          132 ---- x
faz regra de 3 e terá: x= 132/106, que da aproximadamente 1,25 mol

Answer 2

$m_{Na_{2}CO_{3}}=2.23+12+3.16=106g/mol$

$\mathsf{106g\,de\,Na_{2}CO_{3}\rightarrow\,1\,mol}\\\mathsf{132g\,de\,Na_{2}CO_{3}\rightarrow\,\lambda\,mols}$

$\mathsf{\lambda=\dfrac{132}{106}}$

$\boxed{\boxed{\mathsf{\lambda\approx1,24\,mols}}}$