Question

se possivel,aplicando na forma distributiva: 8x-4=6(x-4)
3(7-t)+10t=5(2t-6)
8+2(x-1)=32
3+7(z-4)= -(3z-10)

2-resolva as seguintes questões:

a) 3x/2+1/5=x/4
b)1/2+3x=4
c)y/8-3/4=2y/3
d)x+7/2=4+2x/9
e) 3y-4/7-y/2=5

Answer 1

8x-4=6(x-4)
8x - 4 = 6x - 24
2x +20 = 0
x = -20/2
x= -10

3(7-t)+10t=5(2t-6)
21 + 7t = 10t - 30
51 - 3t = 0
-3t = -51
t= -51/-3
t = 17

8+2(x-1)=32
8 +2x -2 = 32
2x = 32 - 8 +2
2x = 26
x= 26/2
x =13

3+7(z-4)= -(3z-10)
3 + 7z - 28 = -3x + 10
7z -25 = -3x + 10
10z = 35
x= 7/2 ou 3,5
espero ter ajudado