Question

como resolver? X²+X-12=0

Answer 1

x²+x-12=0
a=1 b=1 c=-12
Δ=b²-4.(a).(c)
Δ=(1)²-4.(1).(-12)= 1+48=49
x=-b± √Δ/2.a (sobre 2 vezes A)
x= -(1)± √49/ 2.1
x=-1± 7/ 2
x1= -1 +7/ 2 = 6/2=3
x2= -1 -7/ 2 = -8/2= -4

s={3; -4}