Question

Alguem ajuda ? :B
A)3√20 -3/2√45 + 2/3√125 - √245

B)(2√3-5√2)²

Answer 1

a)
$3 \sqrt{20} - \frac{3 \sqrt{45} }{2} + \frac{2 \sqrt{125} }{3} - \sqrt{245} =$

$3 \sqrt{ 2.5^{2} } - \frac{3 \sqrt{3 ^{2},5 } }{y} + \frac{2 \sqrt{ 5.5^{2} } }{3} - \sqrt{ 7.5^{2} } =$

$6 \sqrt{5} - 9\frac{ \sqrt{5} }{2} + \frac{10 \sqrt{5} }{3} -7 \sqrt{5} =$

$( 6^{} - \frac{9}{2} + \frac{10}{3} -7) \sqrt{5}$

$( \frac{36-27+20-42}{6} ) \sqrt{5}$

$\frac{-13 \sqrt{5} }{6}$

b)
(2√3-5√2)²=

(2√3)²-2(.2√3.5√2)+(5√2)²=

4.3-20√6 +25.2=
12-20√6+50=

62-20√6