Question

dada a equação x^3-12x2+11x=0

Answer 1

$x^3-12x^2+11x=0\\ \\ a) x(x^2-12x+11)=0\\ \\ \boxed{x(x-1)(x-11)=0}\\ \\ b)\\ \boxed{S={0,1,11}}\\ \\ c)\\ \boxed{M=\frac{0+1+11}{3}=4}$

Answer 2

dada a equação x^3-12x2+11x=0

a) x(x^2-12x+11)=0

b) x(x^2-12x+11)=0

x1 = 0

x^2-12x+11 =0

Δ= (-12)² - 4.1.11 = 144-44=100

x= 12 +/- √100 ==> x=12+/-10
           2.1                       2

x1=12+10 ==>x1= 11
         2


x2=12-10 ==>x22= 1
         2


c) M =  0+11+1  ==> M= 4
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