Question

"o vertice da parabola y=(x-m)²?"

Answer 1

y=(x-m)^2 y=(x-m)(x-m) y=x^2 -mx -mx +m^2 y=x^2 -2mx + m^2 a=1, b=-2m, c=m^2 Delta=b^2 -4ac Delta= (-2m)^2 -4*1*m^2 Delta= 4m^2 -4m^4 Delta= 0 Xv= -b/2a Xv=-(-2m)/2*1 Xv=2m/2 Xv=m Yv= -delta/4a Yv= -0/4*1 Yv= 0 O vértice da parábola é o ponto (m,0)