Question

2^2x - 62^x + 5 = 0
(qual o valor da raiz? )

Answer 1

Ola Caio

2^2x - 6*2^x + 5 = 0

y = 2^x

y² - 6y + 5 = 0

delta
d² = 36 - 20 = 16
d = 4

y1 = (6 + 4)/2 = 10/2 = 5
y2 = (6 - 4)/2 = 2/2 = 1

y = 2^x

2^x1 = 5 , x1 = log2(5) 

2^x2 = 1 = 2^0 , x2 = 0