Question

Sendo F(x)=x²+bx+c, calcular F(2),sabendo q F(o)= -3 e F(1)= -1.

Answer 1

f(2) = 2^2 + 2b +c

-3 = 0^2 + 0 + c -> c = -3

-1 = 1^2 +b -3
b = -1 -1 +3 -> b = 1

f(2) = 2^2 + 2*1 -3 <=> f(2) = 4+2-3 = 3

Answer 2

f(x) = x² + bx + c
f(0) = -3 => -3 = (0)² + b.0 + c => c = -3 
f(1) = -1 => -1 = 1 + b + c => b + c = -2 => b - 3 = -2 => b = -2 + 3 => b = 1
..........
f(x) = x² + x - 3
f(2) = (2)² + (2) - 3 => f(2) = 4 + 2 - 3 => f(2) = 3